the pth08000, the 3.3v line, and the wattage of the CPU

Includes but not limited to: SNES, Genesis, Sega CD, PlayStation 1, Nintendo 64, Dreamcast, Game Gear and I guess the Virtual Boy.

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timmeh87
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the pth08000, the 3.3v line, and the wattage of the CPU

Post by timmeh87 »

well i got my new converter today. for those of you too lazy to look up the datasheet, its 4.5-18v input, 1-5v ouput adjustable. so i wired it up with a variable resistor so that i could modify the output voltage. i use a 2kohm resistor in series with a 1kohm trim pot to give me a output range of 2.8 - 3.2v. the trim pot i chose is awesome, it turns like 20 times. so i can control the output of the dc-dc to within about 30 mV of where i want it :D

so i took the system as low as it would go without crashing. 2.86 volts. pleased, i uipped it to 2.9v, and played one race in extreme G. flawless. just to be safe, im going to leave it at 2.95 volts for future use.

with that done, i set out to find if undervolting the CPU would actually have an effect on power consumption. you see, gannon suggested that at a lower voltage the system would draw more current, keeping the total wattage constant (and thus, not affecting heat and battery life)

now, i could have just put my multimeter in series with the 3.3v line, measued the current it drew at a voltage, and figured out the wattage. but for some reason, the 10A function on my meter is broken :(. so i had to be clever about it

i cut myself a 3 inch piece of what was like 28 or 30 guage wire. i tried to measure the resistance, but it was slightly smaller than the resolution of my multimeter. i estimate it to be about .8ohms.

so then i took two test points. (looking at the menu in xG)

Code: Select all

Vo     |  Vr
----------------
2.96v  | 22 mv
3.19v  | 25 mv
where Vo is the output of the dc-dc, and Vr is the voltage drop across the resistor. so, leaving the resistance (R) unknown, we can figure out that the wattage @ 2.96v is 0.06512/R, and the wattage @ 3.19v is 0.07975/R

(how to calculate: I = Vr/R, and the wattage is IVo = VrVo/R)

as you can see, the wattage at 2.96 volts is signifigantly lower :D

i should also mention that there are no vertical lines with this converter = no need for an inductor.

i am pleased.

(ps. codeman, gannon... my math ok?)
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Skyone
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Post by Skyone »

As I posted in another thread, can you post a diagram? I'm HORRIBLE with pots.
Neildo_64
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Post by Neildo_64 »

Awesome job. This could be useful info to add to the sticky. I mean the information about the lowest possible voltage that certain things will run on and maybe the highest possible voltage. Nice discovery.
timmeh87
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Joined: Mon Nov 14, 2005 10:19 pm
Location: Ontario, Canada

Post by timmeh87 »

heres a diagram. i think its right, i did it from memory though. the cap is electrolytic. i didnt use an ouput cap, i figured the N64 had enough of its own.

http://benwiki.gptheatre.co.uk/index.ph ... s_pth08000

oh. and the cap is obviously in backwards... d'oh. ill fix it.

fixed.
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