Nope, that's the beauty of using the diodes. I'm guessing you're not understanding what goes on with the diodes, so here goes. The only important thing to have (though i guess it's not instant death if this isnt the case) is a wall supply with a higher voltage than that of the battery. Assuming you're using schottky diodes, you'll have about a 0.4v drop across each diode. When the battery is connected, say at 7.4v, the input voltage to the DC-DC converter will be 7v. When the wall plug is put in, say at 8.4v, the 0.4v drop across its diode will put the input of the DC-DC converter at 8v. It's not possible to have the same node at a different potential than itself...so one of the diodes "turns off", conveniently the one that's connected to the battery.anotherperson wrote:The issue with that is that I would have to have a switch to disconnect the battery back from the N64 and screen
When the wall plug is put in, the battery diode is reverse biased and allows the battery to source no current at all. Once the battery is not sourcing current, it's like holding a AA in your hand, it does nothing. You can take the battery off and nothing will happen, or you can put in a charging circuit or whatever.
The diodes on the charger chip are just because i'm paranoid. If there was a sudden surge in current because the N64 had to draw an insane amount of polygons or something, the voltage feeding the input to the charger would drop for an instant, and I'm just not sure how the chip would react to that. The diode prevents anything bad from happening.
And they rode off into the sunset
The end