Need Math problem help a bit quick

Motoman · Post by **Motoman** » Mon Nov 07, 2005 7:18 pm

Yea i know this may seem a bit stupid but.....well i need help with a problem and its probably very simple its just that i have no idea how to do it. So if any of you could help me that would help. I need to know this cause we have presentations on the problems assigned to students. anyway here it is:

"If two of the four nonstraight angles formed by the intersection of FH and JK are selected at random, what is the probability that the two angles are congruent?"

Post by **SpongeBuell** » Mon Nov 07, 2005 7:21 pm

Motoman · Post by **Motoman** » Mon Nov 07, 2005 7:23 pm

could you explain how you got that? we have to discuss how we got it in class? (sorry if I'm stupid)

nos_slived · Post by **nos_slived** » Mon Nov 07, 2005 7:23 pm

This may be wrong, but if congruent means same angle, I believe it's right(sorry, I aven't done this stuff in about 2 years). There's a 1 in 3 chance. Say you pick angle 1. Angle 3 is the same as angle one, so unless you can pick angle 1 again, there is only 1 of 3 angles that is the same as angle 1. If you can pick angle 1 twice, which I suppose you can, then it's 2 of 4, or as spongey said, 1 in 2.

Post by **bicostp** » Mon Nov 07, 2005 7:23 pm

I'd have to say 50/50, or 2:1.

IIRC congruent=same measure.

50/50 or 2:1 sounds right, because there are only 2 outcomes:

-The angles are the same
or
-The angles are not the same

No the chances are NOT 25 or 6 to 4.

(good song though)

@nos: 1 to 3? We're only dealing with two angles at a time, so how can it be 3?

daguuy · Post by **daguuy** » Mon Nov 07, 2005 7:24 pm

1/2. there are 2 sets of verticle angles (equal angles on opposite sides of the intersection). that's half of the total 4

EDIT: 1/3

Motoman · Post by **Motoman** » Mon Nov 07, 2005 7:24 pm

Motoman wrote:could you explain how you got that? we have to discuss how we got it in class? (sorry if I'm stupid)

which one is right? and could you tell me how you did that nos?

Thank you.

gamer2 · Post by **gamer2** » Mon Nov 07, 2005 7:24 pm

the awnser is 69

daguuy · Post by **daguuy** » Mon Nov 07, 2005 7:25 pm

it's not 1/3 because you have to pick 2 angles, not the same angle twice

EDIT: i may be wrong, i'll figure it out

EDIT: OK, i got it. NOS is right. if you choose one angle, that leaves 3. only 1 of the 3 is congruent to the 1st angle to chose

MilkMonster · Post by **MilkMonster** » Mon Nov 07, 2005 7:25 pm

gamer2 wrote:the awnser is 69

If your us what number are we thinking of?
69 DUDE!!!

Post by **SpongeBuell** » Mon Nov 07, 2005 7:27 pm

bicostp wrote:I'd have to say 50/50, or 2:1.

IIRC congruent=same measure.

50/50 or 2:1 sounds right, because there are only 2 outcomes:

-The angles are the same
or
-The angles are not the same

No the chances are NOT 25 or 6 to 4.

well, your 50/50 logic is a bit off there, that's like saying "I'll either win the lottery or I won't"

Anyway, think of it like this: there are 2 different angle sizes, 2 of each. This gives us 4 to choose from. now, there are 2 taken at random, with your eyes closed. that means it's 2/4, or 1/2.

nos_slived · Post by **nos_slived** » Mon Nov 07, 2005 7:29 pm

Opposite angles formed by an intersection have equal measures.

Angle 1 = angle 3
Angle 2 = angle 4

If angle 1 is picked as your first one, then you can pick either 1, 2, 3, or 4. If you pick 1 or 3, it's congruent, but 2 or 4 aren't. Therefore, you have a 2/4 chance of them being congruent. 2/4 = 1/2

daguuy · Post by **daguuy** » Mon Nov 07, 2005 7:30 pm

i figured it out, it's 1/3. if you choose one angle, that leaves 3 (you pick 2 angles, not 1 angle twice). only 1 of the 3 is congruent to the 1st angle you chose

madc0w · Post by **madc0w** » Mon Nov 07, 2005 7:32 pm

no, its 1/2, since its not Two DIFFERENT angles, its just two angles.

daguuy · Post by **daguuy** » Mon Nov 07, 2005 7:34 pm

madc0w wrote:no, its 1/2, since its not Two DIFFERENT angles, its just two angles.

so that must mean that when i pick up the same skittle 42 times, i must have picked up 42 skittles